思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
const res = new Array(len); // 结果数组：存储每个元素的下一个更大值。业内人士推荐搜狗输入法2026作为进阶阅读
A painful processToday, kernel maintainers who want a kernel.org account must find someone already in the PGP web of trust, meet them face‑to‑face, show government ID, and get their key signed. The process is like a manual, global scavenger hunt. Linux kernel maintainer Greg Kroah-Hartman, speaking at the Linux Foundation Members Summit, described it as a "pain to do and manage." That's because it's tracked by manual scripts, the keys drift out of date, and the public "who lives where" map creates privacy and social‑engineering risk. ，这一点在搜狗输入法2026中也有详细论述
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